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Linear Equations And Inequalities In Two Variables

Class 10th Mathematics Rajasthan Board Solution
Exercise 4.1
  1. Comparing the ratio a_1/a_2 , b_1/b_2 and c_1/c_2 find out whether the following…
  2. x + y = 3; 3x - 2y = 4 Solve the following pair of linear equations by…
  3. 2x - y = 4; x + y = -1 Solve the following pair of linear equations by…
  4. x + y = 5; 2x + 2y = 10 Solve the following pair of linear equations by…
  5. 3x + y = 2; 2x - 3y = 5 Solve the following pair of linear equations by…
  6. 2x - 5y + 4 = 0; 2x + y - 8 = 0 Solve the following pairs of linear equations…
  7. 3x + 2y = 12; 5x - 2y = 4 Solve the following pairs of linear equations by…
  8. Solve the following pairs of linear equations by graphical method and find the…
Exercise 4.2
  1. x ≥ 2 Show the solution set of the following in equations by graphical method:…
  2. y ≤ -3 Show the solution set of the following in equations by graphical method:…
  3. x - 2y 0 Show the solution set of the following in equations by graphical…
  4. 2x + 3y ≤ 6 Show the solution set of the following in equations by graphical…
  5. |x|≤ 3 Find the solution of the following in equations by graphical method:…
  6. 3x - 2y ≤ x + y - 8 Find the solution of the following in equations by…
  7. |x - y|≥ 1 Find the solution of the following in equations by graphical method:…
Miscellaneous Exercise 4
  1. For what value of k will the pair of equations x + y - 4 = 0, 2x + ky - 3 = 0…
  2. For what value of k will the pair of equations 3x - y = 0 and kx + 5y = 0 have…
  3. The solution of the system of equations kx - y = 2; 6x - 2y = 3 will be unique…
  4. The equations corresponding to the inequations x ≥ 0, y ≥ 0 represent:A. x-axis…
  5. The following statement is true for line corresponding to the inequation y - 3 ≤…
  6. Write the number of equations of the following pair of linear equations: x + 2y…
  7. If the pair of equations 2x + 3y = 7; (a + b)x + (2a - b)y = 21 has infinitely…
  8. Shade the solution set of the inequation |x|≤ 3.
  9. Shade the solution set of the inequality 2x + 3y ≥ 3.
  10. Solve the following pair of linear equations by graphical method and with the…
  11. Solve the following pair of linear equations by graphical method and find the…

Exercise 4.1
Question 1.

Comparing the ratio and find out whether the following pairs of linear equations are consistent or inconsistent.

(i) 2x – 3y = 8; 4x – 6y = 9

(ii) 3x – y = 2; 6x – 2y = 4

(iii) 2x – 2y = 2; 4x – 4y = 5

(iv)


Answer:

For any pair of linear equations to be consistent or inconsistent, we


check the following situations:


a.


In this case, the pair of linear equations is consistent. This means there is unique solution for the given pair of linear equations. The graph of linear equations would be two intersecting lines.


b.


In this case, the pair of linear equations is inconsistent. This means there is no solution for the given pair of linear equations. The graph of linear equations will be two parallel lines.


c.


In this case, the pair of linear equations is dependent and consistent. This means there are infinitely many solutions for the given pair of linear equations. The graph of linear equations will be coincident lines.


(i) 2x – 3y = 8; 4x – 6y = 9


Here, a1 = 2, b1 = – 3, c1 = 8


and a2 = 4, b2 = – 6, c2 = 9





Clearly,


Hence, the given lines are parallel. So the given pair of equation has no solution and it is inconsistent.


(ii) 3x – y = 2; 6x – 2y = 4


Here, a1 = 3, b1 = – 1, c1 = 2


and a2 = 6, b2 = – 2, c2 = 4





Clearly,


Hence, the given lines are dependent and consistent. So the given pair of equation has infinitely many solutions.


(iii) 2x – 2y = 2; 4x – 4y = 5


Here, a1 = 2, b1 = – 2, c1 = 2


and a2 = 4, b2 = – 4, c2 = 5





Clearly,


Hence, the given lines are parallel. So the given pair of equation has no solution and it is inconsistent.


(iv)


Here, , b1 = 2, c1 = 8


and a2 = 2, b2 = 3, c2 = 12





Clearly,


Hence, the given lines are two intersecting lines. So the given pair of equation has unique solution and it is consistent.



Question 2.

Solve the following pair of linear equations by graphical method and find the nature of roots.

x + y = 3; 3x – 2y = 4


Answer:

For a given pair of linear equations in two variables, the graph is represented by two lines.


● If the lines intersect at a point, that point gives the unique solution for the two equations. If there is a unique solution of the given pair of equations, the equations are called consistent.


● If the lines coincide, there are indefinitely many solutions for the pair of linear equations. In this case, each point on the line is a solution. If there are infinitely many solutions of the given pair of linear equations, the equations are called dependent (consistent).


● If the lines are parallel, there is no solution for the pair of linear equations. If there is no solution of the given pair of linear equations, the equations are called inconsistent.


To plot the given pair of linear equations, we substitute x = 0 or y = 0


in the given linear equations to get x and y. To find more points on the


lines, take different values of x related to it and we get different values


for y from the equation.


We get the following tables for the given linear equations.


For x + y = 3


y = 3– x



For 3x – 2y = 4





As seen from the graph, the two lines each other at intersecting point


(2,1). Hence, roots are consistent with unique solution.



Question 3.

Solve the following pair of linear equations by graphical method and find the nature of roots.

2x – y = 4; x + y = –1


Answer:

For a given pair of linear equations in two variables, the graph is represented by two lines.


● If the lines intersect at a point, that point gives the unique solution for the two equations. If there is a unique solution of the given pair of equations, the equations are called consistent.


● If the lines coincide, there are indefinitely many solutions for the pair of linear equations. In this case, each point on the line is a solution. If there are infinitely many solutions of the given pair of linear equations, the equations are called dependent (consistent).


● If the lines are parallel, there is no solution for the pair of linear equations. If there is no solution of the given pair of linear equations, the equations are called inconsistent.


To plot the given pair of linear equations, we substitute x = 0 or y = 0


in the given linear equations to get x and y. To find more points on the


lines, take different values of x related to it and we get different values


for y from the equation.


We get the following tables for the given linear equations.


For 2x – y = 4


y = 2x – 4



For x + y = –1


Y = – 1 – x




As seen from the graph, the two lines each other at intersecting point


(1, – 2). Hence, roots are consistent with unique solution.



Question 4.

Solve the following pair of linear equations by graphical method and find the nature of roots.

x + y = 5; 2x + 2y = 10


Answer:

For a given pair of linear equations in two variables, the graph is represented by two lines.


● If the lines intersect at a point, that point gives the unique solution for the two equations. If there is a unique solution of the given pair of equations, the equations are called consistent.


● If the lines coincide, there are indefinitely many solutions for the pair of linear equations. In this case, each point on the line is a solution. If there are infinitely many solutions of the given pair of linear equations, the equations are called dependent (consistent).


● If the lines are parallel, there is no solution for the pair of linear equations. If there is no solution of the given pair of linear equations, the equations are called inconsistent.


To plot the given pair of linear equations, we substitute x = 0 or y = 0


in the given linear equations to get x and y. To find more points on the


lines, take different values of x related to it and we get different values


for y from the equation.


We get the following tables for the given linear equations.


For x + y = 5


y = 5 – x



For 2x + 2y = 10


2y = 10 – 2x




As seen from the graph and the table, the two lines are parallel and


overlap each other. Hence, roots of the equations are consistent or


dependent with infinitely many solutions.



Question 5.

Solve the following pair of linear equations by graphical method and find the nature of roots.

3x + y = 2; 2x – 3y = 5


Answer:

For a given pair of linear equations in two variables, the graph is represented by two lines.


● If the lines intersect at a point, that point gives the unique solution for the two equations. If there is a unique solution of the given pair of equations, the equations are called consistent.


● If the lines coincide, there are indefinitely many solutions for the pair of linear equations. In this case, each point on the line is a solution. If there are infinitely many solutions of the given pair of linear equations, the equations are called dependent (consistent).


● If the lines are parallel, there is no solution for the pair of linear equations. If there is no solution of the given pair of linear equations, the equations are called inconsistent.


To plot the given pair of linear equations, we substitute x = 0 or y = 0


in the given linear equations to get x and y. To find more points on the


lines, take different values of x related to it and we get different values


for y from the equation.


We get the following tables for the given linear equations.


For 3x + y = 2


y = 2 – 3x



For 2x – 3y = 5


3y = 2x – 5




As seen from the graph, the two lines each other at intersecting point


(1, – 1). Hence, roots of the two lines are consistent with unique solution.



Question 6.

Solve the following pairs of linear equations by graphical method and also find the coordinates of these points where the lines represented by these intersect the y – axis.

2x – 5y + 4 = 0; 2x + y – 8 = 0


Answer:

To plot the given pair of linear equations, we substitute x = 0 or y = 0


in the given linear equations to get x and y. To find more points on the


lines, take different values of x related to it and we get different values


for y from the equation.


We get the following tables for the given linear equations.


For 2x – 5y + 4 = 0


5y = 2x + 4



For 2x + y – 8 = 0


y = 8 – 2x




The coordinates of the points where the lines intersect the y – axis are: (0,0.8) and (0,8).



Question 7.

Solve the following pairs of linear equations by graphical method and also find the coordinates of these points where the lines represented by these intersect the y – axis.

3x + 2y = 12; 5x – 2y = 4


Answer:

To plot the given pair of linear equations, we substitute x = 0 or y = 0


in the given linear equations to get x and y. To find more points on the


lines, take different values of x related to it and we get different values


for y from the equation.


We get the following tables for the given linear equations.


For 3x + 2y = 12


2y = 12 – 3x



For 5x – 2y = 4


2y = 5x – 4




The coordinates of the points where the lines intersect the y – axis are: (0,6) and (0, – 2).



Question 8.

Solve the following pairs of linear equations by graphical method and find the coordinates of the vertices of the triangle formed by lines represented by the triangle formed by lines represented by the pair and the y – axis.

4x – 5y = 20; 3x + 5y = 15


Answer:

To plot the given pair of linear equations, we substitute x = 0 or y = 0


in the given linear equations to get x and y. To find more points on the


lines, take different values of x related to it and we get different values


for y from the equation.


We get the following tables for the given linear equations.


For 4x – 5y = 20


5y = 4x – 20



For 3x + 5y = 15


5y = 3x – 15




The coordinates of the vertices of the triangle formed by lines and the


y – axis are: (0, – 4), (0,3) and (5,0).




Exercise 4.2
Question 1.

Show the solution set of the following in equations by graphical method:

x ≥ 2


Answer:

To find the solution set for x ≥ 2 graphically, we first draw x = 2 which is a line parallel to y – axis (as seen from the graph). x>2 is represented as a shaded region on the right of x = 2, including all the points lying on the line x = 2.




Question 2.

Show the solution set of the following in equations by graphical method:

y ≤ –3


Answer:

To find the solution set for y ≤ –3 graphically, we first draw y = – 3 which


is a line parallel to x – axis (as seen from the graph). y< – 3 is represented


as a shaded region below y = – 3, including all the points lying on the


line y = – 3.




Question 3.

Show the solution set of the following in equations by graphical method:

x – 2y < 0


Answer:

To find the solution set for x – 2y < 0 graphically, we first draw x – 2y = 0


which is a dotted line passing through the origin (as seen from the


graph). x – 2y < 0 is represented as a shaded region above x – 2y = 0,


excluding all the points lying on the line x – 2y = 0.




Question 4.

Show the solution set of the following in equations by graphical method:

2x + 3y ≤ 6


Answer:

To find the solution set for 2x + 3y ≤ 6 graphically, we first draw 2x +


3y = 6,a line as shown in the graph.


As,


(0, 0) satisfies the inequality


2x + 3y < 6, hence


2x + 3y ≤ 6 is represented as a


shaded region below 2x + 3y = 6, including all the points lying on the


line 2x + 3y = 6.




Question 5.

Find the solution of the following in equations by graphical method:

|x|≤ 3


Answer:

To find the solution set for |x|≤ 3 graphically, we first draw x = 3


and x = – 3, two lines drawn parallel to x – axis.


Now,


|0|< 3, satisfies the inequality hence


|x|≤ 3 is represented as


a shaded region between x = 3 and x = – 3, including all the points lying on


the lines x = 3 and x = – 3.




Question 6.

Find the solution of the following in equations by graphical method:

3x – 2y ≤ x + y – 8


Answer:

To find the solution set for 3x – 2y ≤ x + y – 8 graphically, we first


draw the line 3x – 2y = x + y – 8, as shown in the graph. 3x – 2y ≤ x +


y – 8 is represented as a shaded region above the line, including all the


points lying on the line 3x – 2y = x + y – 8.




Question 7.

Find the solution of the following in equations by graphical method:

|x – y|≥ 1


Answer:

To find the solution set for |x – y|≥1 graphically, we first draw x – y = 1


and x – y = – 1, two lines drawn parallel origin. |x – y|≥1 is represented


as a shaded region above and below x – y = 1 and x – y = – 1, including all the


points lying on the lines x – y = 1 and x – y = – 1.





Miscellaneous Exercise 4
Question 1.

For what value of k will the pair of equations x + y – 4 = 0, 2x + ky – 3 = 0 have no solution:
A. 0

B. 2

C. 6

D. 8


Answer:

A pair of linear equations has no solution when,



Given, x + y – 4 = 0


2x + ky – 3 = 0


Here, a1 = 1, b1 = 1, c1 = 4


and a2 = 2, b2 = k, c2 = 3






∴k = 2


Question 2.

For what value of k will the pair of equations 3x – y = 0 and kx + 5y = 0 have infinitely many solutions:
A.

B. 3

C.

D.


Answer:

A pair of linear equations has no solution when,



Given, 3x – y = 0


kx + 5y = 0


Here, a1 = 3, b1 = – 1, c1 = 0


and a2 = k, b2 = 5, c2 = 0







Question 3.

The solution of the system of equations kx – y = 2; 6x – 2y = 3 will be unique of :
A. k = 2

B. k = 3

C. k ≠ 3

D. k ≠ 0


Answer:

A pair of linear equations has no solution when,



Given, kx – y = 2


6x – 2y = 3


Here, a1 = k, b1 = – 1, c1 = 2


and a2 = 6, b2 = – 2, c2 = 3







Question 4.

The equations corresponding to the inequations x ≥ 0, y ≥ 0 represent:
A. x–axis

B. y–axis

C. x and y axis both

D. line x = y


Answer:


As evident from the graph, the inequations x ≥ 0, y ≥ 0 are overlapping


represent x and y axis both.


Question 5.

The following statement is true for line corresponding to the inequation y – 3 ≤ 0:
A. is parallel to x – axis

B. is parallel is y – axis

C. divides x – axis

D. passes through origin


Answer:


As can be seen from the graph inequation y – 3 ≤ 0 is parallel to x – axis.


Question 6.

Write the number of equations of the following pair of linear equations:

x + 2y – 8 = 0; 2x + 4y = 16


Answer:

Here, a1 = 1, b1 = 2, c1 = 8


and a2 = 2, b2 = 4, c2 = 16






This means there are infinitely many solutions for the given pair of


linear equations.



Question 7.

If the pair of equations 2x + 3y = 7; (a + b)x + (2a – b)y = 21 has infinitely many solutions then find the values of a, b.


Answer:

Given, 2x + 3y = 7; (a + b)x + (2a – b)y = 21


We know that a pair of linear equations has infinitely many solutions


when,



Here, a1 = 2, b1 = 3, c1 = 7


and a2 = (a + b), b2 = (2a – b), c2 = 21





A + b = 6 …(i)



2a – b = 9 …(ii)


Adding both the equations we get,


3a = 15


∴a = 5


∴b = 6 – 5


b = 1



Question 8.

Shade the solution set of the inequation |x|≤ 3.


Answer:

To find the solution set for |x|≤ 3 graphically, we first draw x = 3


and x = – 3, two lines drawn parallel to x – axis. |x|≤ 3 is represented as a shaded region between x = 3 and x = – 3, including all the points lying on the lines x = 3 and x = – 3.




Question 9.

Shade the solution set of the inequality

2x + 3y ≥ 3.


Answer:

To find the solution set for 2x + 3y ≥ 3 graphically, we first


draw the line 2x + 3y = 3, as shown in the graph. 2x + 3y ≥ 3 is


represented as a shaded region above the line, including all the


points lying on the line 2x + 3y = 3.




Question 10.

Solve the following pair of linear equations by graphical method and with the help of this find the value of ‘a’ when 4x + 3y = a

x = 3y = 6; 2x – 3y = 12


Answer:

Given, x = 3y = 6, 2x – 3y = 12 and 4x + 3y = a


∴ x = 6


Putting the value of x in 2x – 3y = 12, we get


2 × 6 – 3y = 12


12 – 3y = 12


– 3y = 0


∴ y = 0


Hence the value of a is: a = 4x + 3y


= 4 × 6 + 3 × 0


= 0


So the two linear equations are:


i. 2x – 3y = 12


ii. 4x + 3y = 24


To plot the given pair of linear equations, we substitute x = 0 or y = 0


in the given linear equations to get x and y. To find more points on the


lines, take different values of x related to it and we get different values


for y from the equation.


We get the following tables for the given linear equations.


For 2x – 3y = 12


3y = 2x – 12



For 4x + 3y = 24


3y = 24 – 4x



Now plotting these two equations on graph,




Question 11.

Solve the following pair of linear equations by graphical method and find the coordinates of these points where the lines represented by these intersect the y – axis.

3x + 2y = 12;

5x – 2y = 4


Answer:

To plot the given pair of linear equations, we substitute x = 0 or y = 0


in the given linear equations to get x and y. To find more points on the


lines, take different values of x related to it and we get different values


for y from the equation.


We get the following tables for the given linear equations.


For 3x + 2y = 12


2y = 12 – 3x



For 5x – 2y = 4


2y = 5x – 4




The coordinates of the points where the lines represented by these intersect the y – axis are:


i. (0,6)


ii. (0, – 2)