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Probability

Class 10th Mathematics Rajasthan Board Solution

Exercise 18.1
Question 1.

On tossing a dice once. What is the probability of getting a number greater than 4?


Answer:

The outcomes on tossing a dice can be:


1,2,3,4,5,6.


No. of favorable outcomes = 2 (5,6)


No. of total outcomes = 6


As we know


Probability =


⇒ Probability (Getting a number greater than 4)


=




Question 2.

A coin is tossed twice. What is the probability of getting two heads?


Answer:

The outcomes on tossing a coin twice are:


HH,HT,TH,TT


No. of favorable outcomes = 1


No. of total outcomes = 4


As we know


Probability =


⇒ Probability (Getting two heads)


=



Question 3.

A number is chosen randomly from natural numbers 1 to 17. Find the probability that it is a prime number.


Answer:

Total prime numbers between 1 to 17 are:


2,3,5,7,11,13,17


⇒ Total prime numbers = 7


Total Number between 1 to 17 is = 17


As we know,


Probability =


⇒ Probability (chosen number is prime number)


=



Question 4.

A coin is tossed three times. Find the probability of getting all heads or all tails.


Answer:

The outcomes on tossing a coin three times are:


HHH, HHT, HTH, HTT, THH, THT, TTH, TTT


No. of favorable outcomes = 2 (HHH,TTT)


No. of total outcomes = 8


As we know,


Probability =


⇒ Probability (Getting all heads or all tails)


=


=



Question 5.

Find the probability of getting only 52 Sundays in a non-leap year.


Answer:

Numbers of days in non-leap year = 365


Numbers of weeks in non-leap year =


= 52 weeks + 1 Day


As we have to find probability of only 52 Sundays.


And 52 weeks contain 52 Sundays.


⇒ The extra day should not be Sunday


⇒ Favorable outcomes = Monday, Tuesday, Wednesday, Thursday, Friday, Saturday


And no. of total outcomes = 7


As we know,


Probability =


⇒ probability (Getting only 52 Sundays in a non-leap year)


=



Question 6.

If P(A) = 0.65 then what is the probability of “not A”?


Answer:

As we know,


Probability (“not A”) = 1 – Probability (“A”)


⇒ Probability (“not A”) = 1 – (.65)


⇒ Probability (“Not A”) = .35



Question 7.

Two unbiased coins are tossed simultaneously. Find the probability of getting at most one tail.


Answer:

The outcomes When two unbiased coins are tossed simultaneously:


HH, HT, TH, TT


No. of favorable outcomes = 3


No. of total outcomes = 4


As we know,


Probability =


⇒ Probability (Getting at most one tail)


=



Question 8.

A dice is tossed twice, what is the probability of getting the sum as (i) 9 (ii) 13.


Answer:

The outcomes, When a dice is tossed twice are:


(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)


(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)


(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)


(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)


(5,1), (5,2), (5,3), (5,4) (5,5), (5,6)


(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)


(i) Probability of getting the sum as 9


(6,3), (5,4), (4,5), (3,6)


The no. of favorable outcomes = 4


The no. of total outcomes = 36


As we know,


Probability =


⇒ Probability (Getting the sum as 9)


=



(ii) Probability of sum getting as 13


The no. of favorable outcomes = 0


The no. of total outcomes = 36


As we know,


Probability =


⇒ Probability (Getting the sum as 13)


=


⇒ 0



Question 9.

A bag contains 5 red and 3 white balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is

(i) a white ball?

(ii) not a white ball?


Answer:

(i) The no. of white balls = 3


The no. of total balls in bag = 8


⇒ Probability (Getting a white ball)


=



(ii) Not a white ball or red ball


⇒ The no. of red balls = 5


The no. of total balls in bag = 8


⇒ Probability (Getting not a white ball)


=


=



Question 10.

12 defective pens are accidentally mixed with 132 good ones. It is not possible to just look at a pen and tell whether or not it is defective. One pen is taken out at random from this lot. Determine the probability that the pen taken out is a good one.


Answer:

The no. of Good Pens = 132


The no. of total Pens = Defective Pens + Good Pens


⇒ The no. of total pens = 132 + 12


= 144


Probability (Pen taken out is Good one)


=


=


=



Question 11.

One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting.

(i) a jack of red colour.

(ii) a red card

(iii) an ace of hearts.

(iv) the Queen of diamonds.

(v) a spade


Answer:

(i) The no. of jack of red colour = 2


The total no. of cards = 52


Probability (Getting a jack of red colour)


=


=


(ii) The no. of Red cards = 26


The no. of total cards = 52


Probability (Getting a red card )


=


=


(iii) The no. of ace of hearts = 1


The no. of total cards = 52


Probability (Getting an ace of hearts)


=


=


(iv)The no. of queen of diamonds = 1


The no. of total cards = 52


Probability (Getting the queen of diamonds)


=


=


(v)The no of Spade cards = 13


The no. of total cards = 52


Probability (Getting a Spade) =



=